3(y-2)+4=-3y+4

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Solution for 3(y-2)+4=-3y+4 equation: 



3(y-2)+4=-3y+4

We move all terms to the left:

3(y-2)+4-(-3y+4)=0

We multiply parentheses

3y-(-3y+4)-6+4=0

We get rid of parentheses

3y+3y-4-6+4=0

We add all the numbers together, and all the variables

6y-6=0

We move all terms containing y to the left, all other terms to the right

6y=6

y=6/6

y=1

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