3(y-2)+5=3y-1

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Solution for 3(y-2)+5=3y-1 equation:


Simplifying
3(y + -2) + 5 = 3y + -1

Reorder the terms:
3(-2 + y) + 5 = 3y + -1
(-2 * 3 + y * 3) + 5 = 3y + -1
(-6 + 3y) + 5 = 3y + -1

Reorder the terms:
-6 + 5 + 3y = 3y + -1

Combine like terms: -6 + 5 = -1
-1 + 3y = 3y + -1

Reorder the terms:
-1 + 3y = -1 + 3y

Add '1' to each side of the equation.
-1 + 1 + 3y = -1 + 1 + 3y

Combine like terms: -1 + 1 = 0
0 + 3y = -1 + 1 + 3y
3y = -1 + 1 + 3y

Combine like terms: -1 + 1 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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