3(y-2)+6=2(y-3)-5

Solution for 3(y-2)+6=2(y-3)-5 equation:

Simplifying
3(y + -2) + 6 = 2(y + -3) + -5

Reorder the terms:
3(-2 + y) + 6 = 2(y + -3) + -5
(-2 * 3 + y * 3) + 6 = 2(y + -3) + -5
(-6 + 3y) + 6 = 2(y + -3) + -5

Reorder the terms:
-6 + 6 + 3y = 2(y + -3) + -5

Combine like terms: -6 + 6 = 0
0 + 3y = 2(y + -3) + -5
3y = 2(y + -3) + -5

Reorder the terms:
3y = 2(-3 + y) + -5
3y = (-3 * 2 + y * 2) + -5
3y = (-6 + 2y) + -5

Reorder the terms:
3y = -6 + -5 + 2y

Combine like terms: -6 + -5 = -11
3y = -11 + 2y

Solving
3y = -11 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
3y + -2y = -11 + 2y + -2y

Combine like terms: 3y + -2y = 1y
1y = -11 + 2y + -2y

Combine like terms: 2y + -2y = 0
1y = -11 + 0
1y = -11

Divide each side by '1'.
y = -11

Simplifying
y = -11