3(y-2)+y=7(2y+1)-3

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Solution for 3(y-2)+y=7(2y+1)-3 equation:


Simplifying
3(y + -2) + y = 7(2y + 1) + -3

Reorder the terms:
3(-2 + y) + y = 7(2y + 1) + -3
(-2 * 3 + y * 3) + y = 7(2y + 1) + -3
(-6 + 3y) + y = 7(2y + 1) + -3

Combine like terms: 3y + y = 4y
-6 + 4y = 7(2y + 1) + -3

Reorder the terms:
-6 + 4y = 7(1 + 2y) + -3
-6 + 4y = (1 * 7 + 2y * 7) + -3
-6 + 4y = (7 + 14y) + -3

Reorder the terms:
-6 + 4y = 7 + -3 + 14y

Combine like terms: 7 + -3 = 4
-6 + 4y = 4 + 14y

Solving
-6 + 4y = 4 + 14y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-14y' to each side of the equation.
-6 + 4y + -14y = 4 + 14y + -14y

Combine like terms: 4y + -14y = -10y
-6 + -10y = 4 + 14y + -14y

Combine like terms: 14y + -14y = 0
-6 + -10y = 4 + 0
-6 + -10y = 4

Add '6' to each side of the equation.
-6 + 6 + -10y = 4 + 6

Combine like terms: -6 + 6 = 0
0 + -10y = 4 + 6
-10y = 4 + 6

Combine like terms: 4 + 6 = 10
-10y = 10

Divide each side by '-10'.
y = -1

Simplifying
y = -1

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