3(y-2)-2(3y+5)=17

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Solution for 3(y-2)-2(3y+5)=17 equation: 



3(y-2)-2(3y+5)=17

We move all terms to the left:

3(y-2)-2(3y+5)-(17)=0

We multiply parentheses

3y-6y-6-10-17=0

We add all the numbers together, and all the variables

-3y-33=0

We move all terms containing y to the left, all other terms to the right

-3y=33

y=33/-3

y=-11

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