3(y-2)-5=4y-28

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Solution for 3(y-2)-5=4y-28 equation: 



3(y-2)-5=4y-28

We move all terms to the left:

3(y-2)-5-(4y-28)=0

We multiply parentheses

3y-(4y-28)-6-5=0

We get rid of parentheses

3y-4y+28-6-5=0

We add all the numbers together, and all the variables

-1y+17=0

We move all terms containing y to the left, all other terms to the right

-y=-17

y=-17/-1

y=+17

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