3(y-2)-7=2(y-3)-3(y+5)

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Solution for 3(y-2)-7=2(y-3)-3(y+5) equation: 



3(y-2)-7=2(y-3)-3(y+5)

We move all terms to the left:

3(y-2)-7-(2(y-3)-3(y+5))=0

We multiply parentheses

3y-(2(y-3)-3(y+5))-6-7=0



We calculate terms in parentheses: -(2(y-3)-3(y+5)), so:

2(y-3)-3(y+5)

We multiply parentheses

2y-3y-6-15

We add all the numbers together, and all the variables

-1y-21

Back to the equation:

-(-1y-21)



We add all the numbers together, and all the variables

3y-(-1y-21)-13=0

We get rid of parentheses

3y+1y+21-13=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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