3(y-2)=-(2y-4)

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Solution for 3(y-2)=-(2y-4) equation: 



3(y-2)=-(2y-4)

We move all terms to the left:

3(y-2)-(-(2y-4))=0

We multiply parentheses

3y-(-(2y-4))-6=0



We calculate terms in parentheses: -(-(2y-4)), so:

-(2y-4)

We get rid of parentheses

-2y+4

Back to the equation:

-(-2y+4)



We get rid of parentheses

3y+2y-4-6=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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