3(y-2)=-2(3y-4)

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Solution for 3(y-2)=-2(3y-4) equation: 



3(y-2)=-2(3y-4)

We move all terms to the left:

3(y-2)-(-2(3y-4))=0

We multiply parentheses

3y-(-2(3y-4))-6=0



We calculate terms in parentheses: -(-2(3y-4)), so:

-2(3y-4)

We multiply parentheses

-6y+8

Back to the equation:

-(-6y+8)



We get rid of parentheses

3y+6y-8-6=0

We add all the numbers together, and all the variables

9y-14=0

We move all terms containing y to the left, all other terms to the right

9y=14

y=14/9

y=1+5/9

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