3(y-2)=-3y+12

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Solution for 3(y-2)=-3y+12 equation: 



3(y-2)=-3y+12

We move all terms to the left:

3(y-2)-(-3y+12)=0

We multiply parentheses

3y-(-3y+12)-6=0

We get rid of parentheses

3y+3y-12-6=0

We add all the numbers together, and all the variables

6y-18=0

We move all terms containing y to the left, all other terms to the right

6y=18

y=18/6

y=3

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