3(y-2)=2(2y+3)

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Solution for 3(y-2)=2(2y+3) equation: 



3(y-2)=2(2y+3)

We move all terms to the left:

3(y-2)-(2(2y+3))=0

We multiply parentheses

3y-(2(2y+3))-6=0



We calculate terms in parentheses: -(2(2y+3)), so:

2(2y+3)

We multiply parentheses

4y+6

Back to the equation:

-(4y+6)



We get rid of parentheses

3y-4y-6-6=0

We add all the numbers together, and all the variables

-1y-12=0

We move all terms containing y to the left, all other terms to the right

-y=12

y=12/-1

y=-12

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