3(y-2)=2(y+1)

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Solution for 3(y-2)=2(y+1) equation:



3(y-2)=2(y+1)
We move all terms to the left:
3(y-2)-(2(y+1))=0
We multiply parentheses
3y-(2(y+1))-6=0
We calculate terms in parentheses: -(2(y+1)), so:
2(y+1)
We multiply parentheses
2y+2
Back to the equation:
-(2y+2)
We get rid of parentheses
3y-2y-2-6=0
We add all the numbers together, and all the variables
y-8=0
We move all terms containing y to the left, all other terms to the right
y=8

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