3(y-2)=2(y+1)+y-8

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Solution for 3(y-2)=2(y+1)+y-8 equation: 



3(y-2)=2(y+1)+y-8

We move all terms to the left:

3(y-2)-(2(y+1)+y-8)=0

We multiply parentheses

3y-(2(y+1)+y-8)-6=0



We calculate terms in parentheses: -(2(y+1)+y-8), so:

2(y+1)+y-8

We add all the numbers together, and all the variables

y+2(y+1)-8

We multiply parentheses

y+2y+2-8

We add all the numbers together, and all the variables

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

3y-3y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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