3(y-2)=2(y-2-3)

Solution for 3(y-2)=2(y-2-3) equation:

3(y-2)=2(y-2-3)

We move all terms to the left:

3(y-2)-(2(y-2-3))=0

We add all the numbers together, and all the variables

3(y-2)-(2(y-5))=0

We multiply parentheses

3y-(2(y-5))-6=0


We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)


We get rid of parentheses

3y-2y+10-6=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4