3(y-2)=4(3-y)

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Solution for 3(y-2)=4(3-y) equation: 



3(y-2)=4(3-y)

We move all terms to the left:

3(y-2)-(4(3-y))=0

We add all the numbers together, and all the variables

3(y-2)-(4(-1y+3))=0

We multiply parentheses

3y-(4(-1y+3))-6=0



We calculate terms in parentheses: -(4(-1y+3)), so:

4(-1y+3)

We multiply parentheses

-4y+12

Back to the equation:

-(-4y+12)



We get rid of parentheses

3y+4y-12-6=0

We add all the numbers together, and all the variables

7y-18=0

We move all terms containing y to the left, all other terms to the right

7y=18

y=18/7

y=2+4/7

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