3(y-2)=6(y-1)+-3y

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Solution for 3(y-2)=6(y-1)+-3y equation: 



3(y-2)=6(y-1)+-3y

We move all terms to the left:

3(y-2)-(6(y-1)+-3y)=0

We use the square of the difference formula

3(y-2)-(6(y-1)-3y)=0

We multiply parentheses

3y-(6(y-1)-3y)-6=0



We calculate terms in parentheses: -(6(y-1)-3y), so:

6(y-1)-3y

We add all the numbers together, and all the variables

-3y+6(y-1)

We multiply parentheses

-3y+6y-6

We add all the numbers together, and all the variables

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

3y-3y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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