3(y-2)=7(y+8)

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Solution for 3(y-2)=7(y+8) equation: 



3(y-2)=7(y+8)

We move all terms to the left:

3(y-2)-(7(y+8))=0

We multiply parentheses

3y-(7(y+8))-6=0



We calculate terms in parentheses: -(7(y+8)), so:

7(y+8)

We multiply parentheses

7y+56

Back to the equation:

-(7y+56)



We get rid of parentheses

3y-7y-56-6=0

We add all the numbers together, and all the variables

-4y-62=0

We move all terms containing y to the left, all other terms to the right

-4y=62

y=62/-4

y=-15+1/2

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