3(y-22)+2(y-4)=16

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Solution for 3(y-22)+2(y-4)=16 equation: 



3(y-22)+2(y-4)=16

We move all terms to the left:

3(y-22)+2(y-4)-(16)=0

We multiply parentheses

3y+2y-66-8-16=0

We add all the numbers together, and all the variables

5y-90=0

We move all terms containing y to the left, all other terms to the right

5y=90

y=90/5

y=18

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