3(y-3)+2(y+1)=2(y-1)

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Solution for 3(y-3)+2(y+1)=2(y-1) equation:


Simplifying
3(y + -3) + 2(y + 1) = 2(y + -1)

Reorder the terms:
3(-3 + y) + 2(y + 1) = 2(y + -1)
(-3 * 3 + y * 3) + 2(y + 1) = 2(y + -1)
(-9 + 3y) + 2(y + 1) = 2(y + -1)

Reorder the terms:
-9 + 3y + 2(1 + y) = 2(y + -1)
-9 + 3y + (1 * 2 + y * 2) = 2(y + -1)
-9 + 3y + (2 + 2y) = 2(y + -1)

Reorder the terms:
-9 + 2 + 3y + 2y = 2(y + -1)

Combine like terms: -9 + 2 = -7
-7 + 3y + 2y = 2(y + -1)

Combine like terms: 3y + 2y = 5y
-7 + 5y = 2(y + -1)

Reorder the terms:
-7 + 5y = 2(-1 + y)
-7 + 5y = (-1 * 2 + y * 2)
-7 + 5y = (-2 + 2y)

Solving
-7 + 5y = -2 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-7 + 5y + -2y = -2 + 2y + -2y

Combine like terms: 5y + -2y = 3y
-7 + 3y = -2 + 2y + -2y

Combine like terms: 2y + -2y = 0
-7 + 3y = -2 + 0
-7 + 3y = -2

Add '7' to each side of the equation.
-7 + 7 + 3y = -2 + 7

Combine like terms: -7 + 7 = 0
0 + 3y = -2 + 7
3y = -2 + 7

Combine like terms: -2 + 7 = 5
3y = 5

Divide each side by '3'.
y = 1.666666667

Simplifying
y = 1.666666667

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