3(y-3)+2y=6

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Solution for 3(y-3)+2y=6 equation:



3(y-3)+2y=6
We move all terms to the left:
3(y-3)+2y-(6)=0
We add all the numbers together, and all the variables
2y+3(y-3)-6=0
We multiply parentheses
2y+3y-9-6=0
We add all the numbers together, and all the variables
5y-15=0
We move all terms containing y to the left, all other terms to the right
5y=15
y=15/5
y=3

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