3(y-3)+3y=6(y-5)

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Solution for 3(y-3)+3y=6(y-5) equation:


Simplifying
3(y + -3) + 3y = 6(y + -5)

Reorder the terms:
3(-3 + y) + 3y = 6(y + -5)
(-3 * 3 + y * 3) + 3y = 6(y + -5)
(-9 + 3y) + 3y = 6(y + -5)

Combine like terms: 3y + 3y = 6y
-9 + 6y = 6(y + -5)

Reorder the terms:
-9 + 6y = 6(-5 + y)
-9 + 6y = (-5 * 6 + y * 6)
-9 + 6y = (-30 + 6y)

Add '-6y' to each side of the equation.
-9 + 6y + -6y = -30 + 6y + -6y

Combine like terms: 6y + -6y = 0
-9 + 0 = -30 + 6y + -6y
-9 = -30 + 6y + -6y

Combine like terms: 6y + -6y = 0
-9 = -30 + 0
-9 = -30

Solving
-9 = -30

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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