3(y-3)+4(y+1)=

Solution for 3(y-3)+4(y+1)= equation:

Simplifying
3(y + -3) + 4(y + 1) = 0

Reorder the terms:
3(-3 + y) + 4(y + 1) = 0
(-3 * 3 + y * 3) + 4(y + 1) = 0
(-9 + 3y) + 4(y + 1) = 0

Reorder the terms:
-9 + 3y + 4(1 + y) = 0
-9 + 3y + (1 * 4 + y * 4) = 0
-9 + 3y + (4 + 4y) = 0

Reorder the terms:
-9 + 4 + 3y + 4y = 0

Combine like terms: -9 + 4 = -5
-5 + 3y + 4y = 0

Combine like terms: 3y + 4y = 7y
-5 + 7y = 0

Solving
-5 + 7y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 7y = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 7y = 0 + 5
7y = 0 + 5

Combine like terms: 0 + 5 = 5
7y = 5

Divide each side by '7'.
y = 0.7142857143

Simplifying
y = 0.7142857143