3(y-3)-(4-y)=2(y1)

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Solution for 3(y-3)-(4-y)=2(y1) equation:



3(y-3)-(4-y)=2(y1)
We move all terms to the left:
3(y-3)-(4-y)-(2(y1))=0
determiningTheFunctionDomain 3(y-3)-(4-y)-2y1=0
We add all the numbers together, and all the variables
3(y-3)-(-1y+4)-2y1=0
We add all the numbers together, and all the variables
-2y+3(y-3)-(-1y+4)=0
We multiply parentheses
-2y+3y-(-1y+4)-9=0
We get rid of parentheses
-2y+3y+1y-4-9=0
We add all the numbers together, and all the variables
2y-13=0
We move all terms containing y to the left, all other terms to the right
2y=13
y=13/2
y=6+1/2

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