3(y-3)-(4y+2)=1

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Solution for 3(y-3)-(4y+2)=1 equation: 


Simplifying
3(y + -3) + -1(4y + 2) = 1

Reorder the terms:
3(-3 + y) + -1(4y + 2) = 1
(-3 * 3 + y * 3) + -1(4y + 2) = 1
(-9 + 3y) + -1(4y + 2) = 1

Reorder the terms:
-9 + 3y + -1(2 + 4y) = 1
-9 + 3y + (2 * -1 + 4y * -1) = 1
-9 + 3y + (-2 + -4y) = 1

Reorder the terms:
-9 + -2 + 3y + -4y = 1

Combine like terms: -9 + -2 = -11
-11 + 3y + -4y = 1

Combine like terms: 3y + -4y = -1y
-11 + -1y = 1

Solving
-11 + -1y = 1

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + -1y = 1 + 11

Combine like terms: -11 + 11 = 0
0 + -1y = 1 + 11
-1y = 1 + 11

Combine like terms: 1 + 11 = 12
-1y = 12

Divide each side by '-1'.
y = -12

Simplifying
y = -12

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