3(y-3)-(y+2)=5(y-2)-6(y-2)

Solution for 3(y-3)-(y+2)=5(y-2)-6(y-2) equation:

3(y-3)-(y+2)=5(y-2)-6(y-2)

We move all terms to the left:

3(y-3)-(y+2)-(5(y-2)-6(y-2))=0

We multiply parentheses

3y-(y+2)-(5(y-2)-6(y-2))-9=0

We get rid of parentheses

3y-y-(5(y-2)-6(y-2))-2-9=0


We calculate terms in parentheses: -(5(y-2)-6(y-2)), so:

5(y-2)-6(y-2)

We multiply parentheses

5y-6y-10+12

We add all the numbers together, and all the variables

-1y+2

Back to the equation:

-(-1y+2)


We add all the numbers together, and all the variables

2y-(-1y+2)-11=0

We get rid of parentheses

2y+1y-2-11=0

We add all the numbers together, and all the variables

3y-13=0

We move all terms containing y to the left, all other terms to the right

3y=13

y=13/3

y=4+1/3