3(y-3)-1=-2(-7y+2)-7y

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Solution for 3(y-3)-1=-2(-7y+2)-7y equation: 



3(y-3)-1=-2(-7y+2)-7y

We move all terms to the left:

3(y-3)-1-(-2(-7y+2)-7y)=0

We multiply parentheses

3y-(-2(-7y+2)-7y)-9-1=0



We calculate terms in parentheses: -(-2(-7y+2)-7y), so:

-2(-7y+2)-7y

We add all the numbers together, and all the variables

-7y-2(-7y+2)

We multiply parentheses

-7y+14y-4

We add all the numbers together, and all the variables

7y-4

Back to the equation:

-(7y-4)



We add all the numbers together, and all the variables

3y-(7y-4)-10=0

We get rid of parentheses

3y-7y+4-10=0

We add all the numbers together, and all the variables

-4y-6=0

We move all terms containing y to the left, all other terms to the right

-4y=6

y=6/-4

y=-1+1/2

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