3(y-3)-4=-3(-4y+9)-5y

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Solution for 3(y-3)-4=-3(-4y+9)-5y equation: 



3(y-3)-4=-3(-4y+9)-5y

We move all terms to the left:

3(y-3)-4-(-3(-4y+9)-5y)=0

We multiply parentheses

3y-(-3(-4y+9)-5y)-9-4=0



We calculate terms in parentheses: -(-3(-4y+9)-5y), so:

-3(-4y+9)-5y

We add all the numbers together, and all the variables

-5y-3(-4y+9)

We multiply parentheses

-5y+12y-27

We add all the numbers together, and all the variables

7y-27

Back to the equation:

-(7y-27)



We add all the numbers together, and all the variables

3y-(7y-27)-13=0

We get rid of parentheses

3y-7y+27-13=0

We add all the numbers together, and all the variables

-4y+14=0

We move all terms containing y to the left, all other terms to the right

-4y=-14

y=-14/-4

y=3+1/2

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