3(y-3)-7=-4(-7y+3)-9y

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Solution for 3(y-3)-7=-4(-7y+3)-9y equation: 



3(y-3)-7=-4(-7y+3)-9y

We move all terms to the left:

3(y-3)-7-(-4(-7y+3)-9y)=0

We multiply parentheses

3y-(-4(-7y+3)-9y)-9-7=0



We calculate terms in parentheses: -(-4(-7y+3)-9y), so:

-4(-7y+3)-9y

We add all the numbers together, and all the variables

-9y-4(-7y+3)

We multiply parentheses

-9y+28y-12

We add all the numbers together, and all the variables

19y-12

Back to the equation:

-(19y-12)



We add all the numbers together, and all the variables

3y-(19y-12)-16=0

We get rid of parentheses

3y-19y+12-16=0

We add all the numbers together, and all the variables

-16y-4=0

We move all terms containing y to the left, all other terms to the right

-16y=4

y=4/-16

y=-1/4

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