3(y-3)-9=-3(-7y+5)-6y

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Solution for 3(y-3)-9=-3(-7y+5)-6y equation: 



3(y-3)-9=-3(-7y+5)-6y

We move all terms to the left:

3(y-3)-9-(-3(-7y+5)-6y)=0

We multiply parentheses

3y-(-3(-7y+5)-6y)-9-9=0



We calculate terms in parentheses: -(-3(-7y+5)-6y), so:

-3(-7y+5)-6y

We add all the numbers together, and all the variables

-6y-3(-7y+5)

We multiply parentheses

-6y+21y-15

We add all the numbers together, and all the variables

15y-15

Back to the equation:

-(15y-15)



We add all the numbers together, and all the variables

3y-(15y-15)-18=0

We get rid of parentheses

3y-15y+15-18=0

We add all the numbers together, and all the variables

-12y-3=0

We move all terms containing y to the left, all other terms to the right

-12y=3

y=3/-12

y=-1/4

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