3(y-3)-9=-4(-4y+3)-4y

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Solution for 3(y-3)-9=-4(-4y+3)-4y equation: 



3(y-3)-9=-4(-4y+3)-4y

We move all terms to the left:

3(y-3)-9-(-4(-4y+3)-4y)=0

We multiply parentheses

3y-(-4(-4y+3)-4y)-9-9=0



We calculate terms in parentheses: -(-4(-4y+3)-4y), so:

-4(-4y+3)-4y

We add all the numbers together, and all the variables

-4y-4(-4y+3)

We multiply parentheses

-4y+16y-12

We add all the numbers together, and all the variables

12y-12

Back to the equation:

-(12y-12)



We add all the numbers together, and all the variables

3y-(12y-12)-18=0

We get rid of parentheses

3y-12y+12-18=0

We add all the numbers together, and all the variables

-9y-6=0

We move all terms containing y to the left, all other terms to the right

-9y=6

y=6/-9

y=-2/3

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