3(y-3)=-8y+2

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Solution for 3(y-3)=-8y+2 equation: 



3(y-3)=-8y+2

We move all terms to the left:

3(y-3)-(-8y+2)=0

We multiply parentheses

3y-(-8y+2)-9=0

We get rid of parentheses

3y+8y-2-9=0

We add all the numbers together, and all the variables

11y-11=0

We move all terms containing y to the left, all other terms to the right

11y=11

y=11/11

y=1

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