3(y-3)=2(1-4y)

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Solution for 3(y-3)=2(1-4y) equation: 



3(y-3)=2(1-4y)

We move all terms to the left:

3(y-3)-(2(1-4y))=0

We add all the numbers together, and all the variables

3(y-3)-(2(-4y+1))=0

We multiply parentheses

3y-(2(-4y+1))-9=0



We calculate terms in parentheses: -(2(-4y+1)), so:

2(-4y+1)

We multiply parentheses

-8y+2

Back to the equation:

-(-8y+2)



We get rid of parentheses

3y+8y-2-9=0

We add all the numbers together, and all the variables

11y-11=0

We move all terms containing y to the left, all other terms to the right

11y=11

y=11/11

y=1

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