3(y-3)=2y-9+y=

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Solution for 3(y-3)=2y-9+y= equation: 



3(y-3)=2y-9+y=

We move all terms to the left:

3(y-3)-(2y-9+y)=0

We add all the numbers together, and all the variables

3(y-3)-(3y-9)=0

We multiply parentheses

3y-(3y-9)-9=0

We get rid of parentheses

3y-3y+9-9=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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