3(y-3)=3y+4-2(-9y-1)

Solution for 3(y-3)=3y+4-2(-9y-1) equation:

3(y-3)=3y+4-2(-9y-1)

We move all terms to the left:

3(y-3)-(3y+4-2(-9y-1))=0

We multiply parentheses

3y-(3y+4-2(-9y-1))-9=0


We calculate terms in parentheses: -(3y+4-2(-9y-1)), so:

3y+4-2(-9y-1)

determiningTheFunctionDomain
3y-2(-9y-1)+4

We multiply parentheses

3y+18y+2+4

We add all the numbers together, and all the variables

21y+6

Back to the equation:

-(21y+6)


We get rid of parentheses

3y-21y-6-9=0

We add all the numbers together, and all the variables

-18y-15=0

We move all terms containing y to the left, all other terms to the right

-18y=15

y=15/-18

y=-5/6