3(y-3)=7y+5-2(-4y-2)

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Solution for 3(y-3)=7y+5-2(-4y-2) equation: 



3(y-3)=7y+5-2(-4y-2)

We move all terms to the left:

3(y-3)-(7y+5-2(-4y-2))=0

We multiply parentheses

3y-(7y+5-2(-4y-2))-9=0



We calculate terms in parentheses: -(7y+5-2(-4y-2)), so:

7y+5-2(-4y-2)

determiningTheFunctionDomain
7y-2(-4y-2)+5

We multiply parentheses

7y+8y+4+5

We add all the numbers together, and all the variables

15y+9

Back to the equation:

-(15y+9)



We get rid of parentheses

3y-15y-9-9=0

We add all the numbers together, and all the variables

-12y-18=0

We move all terms containing y to the left, all other terms to the right

-12y=18

y=18/-12

y=-1+1/2

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