3(y-3)=7y+7

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Solution for 3(y-3)=7y+7 equation: 



3(y-3)=7y+7

We move all terms to the left:

3(y-3)-(7y+7)=0

We multiply parentheses

3y-(7y+7)-9=0

We get rid of parentheses

3y-7y-7-9=0

We add all the numbers together, and all the variables

-4y-16=0

We move all terms containing y to the left, all other terms to the right

-4y=16

y=16/-4

y=-4

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