3(y-3)=9y+1-3(-2y-2)

Solution for 3(y-3)=9y+1-3(-2y-2) equation:

3(y-3)=9y+1-3(-2y-2)

We move all terms to the left:

3(y-3)-(9y+1-3(-2y-2))=0

We multiply parentheses

3y-(9y+1-3(-2y-2))-9=0


We calculate terms in parentheses: -(9y+1-3(-2y-2)), so:

9y+1-3(-2y-2)

determiningTheFunctionDomain
9y-3(-2y-2)+1

We multiply parentheses

9y+6y+6+1

We add all the numbers together, and all the variables

15y+7

Back to the equation:

-(15y+7)


We get rid of parentheses

3y-15y-7-9=0

We add all the numbers together, and all the variables

-12y-16=0

We move all terms containing y to the left, all other terms to the right

-12y=16

y=16/-12

y=-1+1/3