3(y-4)+10y=30y-90

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Solution for 3(y-4)+10y=30y-90 equation: 



3(y-4)+10y=30y-90

We move all terms to the left:

3(y-4)+10y-(30y-90)=0

We add all the numbers together, and all the variables

10y+3(y-4)-(30y-90)=0

We multiply parentheses

10y+3y-(30y-90)-12=0

We get rid of parentheses

10y+3y-30y+90-12=0

We add all the numbers together, and all the variables

-17y+78=0

We move all terms containing y to the left, all other terms to the right

-17y=-78

y=-78/-17

y=4+10/17

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