3(y-4)+10y=30y-90

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Solution for 3(y-4)+10y=30y-90 equation:



3(y-4)+10y=30y-90
We move all terms to the left:
3(y-4)+10y-(30y-90)=0
We add all the numbers together, and all the variables
10y+3(y-4)-(30y-90)=0
We multiply parentheses
10y+3y-(30y-90)-12=0
We get rid of parentheses
10y+3y-30y+90-12=0
We add all the numbers together, and all the variables
-17y+78=0
We move all terms containing y to the left, all other terms to the right
-17y=-78
y=-78/-17
y=4+10/17

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