3(y-4)+2(4y-2)=6

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Solution for 3(y-4)+2(4y-2)=6 equation:


Simplifying
3(y + -4) + 2(4y + -2) = 6

Reorder the terms:
3(-4 + y) + 2(4y + -2) = 6
(-4 * 3 + y * 3) + 2(4y + -2) = 6
(-12 + 3y) + 2(4y + -2) = 6

Reorder the terms:
-12 + 3y + 2(-2 + 4y) = 6
-12 + 3y + (-2 * 2 + 4y * 2) = 6
-12 + 3y + (-4 + 8y) = 6

Reorder the terms:
-12 + -4 + 3y + 8y = 6

Combine like terms: -12 + -4 = -16
-16 + 3y + 8y = 6

Combine like terms: 3y + 8y = 11y
-16 + 11y = 6

Solving
-16 + 11y = 6

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 11y = 6 + 16

Combine like terms: -16 + 16 = 0
0 + 11y = 6 + 16
11y = 6 + 16

Combine like terms: 6 + 16 = 22
11y = 22

Divide each side by '11'.
y = 2

Simplifying
y = 2

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