3(y-4)+2(y+1)=10

Solution for 3(y-4)+2(y+1)=10 equation:

Simplifying
3(y + -4) + 2(y + 1) = 10

Reorder the terms:
3(-4 + y) + 2(y + 1) = 10
(-4 * 3 + y * 3) + 2(y + 1) = 10
(-12 + 3y) + 2(y + 1) = 10

Reorder the terms:
-12 + 3y + 2(1 + y) = 10
-12 + 3y + (1 * 2 + y * 2) = 10
-12 + 3y + (2 + 2y) = 10

Reorder the terms:
-12 + 2 + 3y + 2y = 10

Combine like terms: -12 + 2 = -10
-10 + 3y + 2y = 10

Combine like terms: 3y + 2y = 5y
-10 + 5y = 10

Solving
-10 + 5y = 10

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 5y = 10 + 10

Combine like terms: -10 + 10 = 0
0 + 5y = 10 + 10
5y = 10 + 10

Combine like terms: 10 + 10 = 20
5y = 20

Divide each side by '5'.
y = 4

Simplifying
y = 4