3(y-4)+2(y+10)=16

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Solution for 3(y-4)+2(y+10)=16 equation: 



3(y-4)+2(y+10)=16

We move all terms to the left:

3(y-4)+2(y+10)-(16)=0

We multiply parentheses

3y+2y-12+20-16=0

We add all the numbers together, and all the variables

5y-8=0

We move all terms containing y to the left, all other terms to the right

5y=8

y=8/5

y=1+3/5

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