3(y-4)+5(y+3)=43

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Solution for 3(y-4)+5(y+3)=43 equation: 



3(y-4)+5(y+3)=43

We move all terms to the left:

3(y-4)+5(y+3)-(43)=0

We multiply parentheses

3y+5y-12+15-43=0

We add all the numbers together, and all the variables

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5

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