3(y-4)+6(y+1)=57

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Solution for 3(y-4)+6(y+1)=57 equation:


3(y-4)+6(y+1)=57

We simplify the equation to the form, which is simple to understand 
3(y-4)+6(y+1)=57

Reorder the terms in parentheses
+(+3y-12)+6*(y+1)=57

Remove unnecessary parentheses
+3y-12+6+*(+y+1+)=+57

Reorder the terms in parentheses
+3y-12+(+6y+6)=57

Remove unnecessary parentheses
+3y-12+6y+6=+57

We move all terms containing y to the left and all other terms to the right. 
+3y+6y=+57+12-6

We simplify left and right side of the equation. 
+9y=+63

We divide both sides of the equation by 9 to get y. 
y=7

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