3(y-4)+6=18

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Solution for 3(y-4)+6=18 equation: 



3(y-4)+6=18

We move all terms to the left:

3(y-4)+6-(18)=0

We add all the numbers together, and all the variables

3(y-4)-12=0

We multiply parentheses

3y-12-12=0

We add all the numbers together, and all the variables

3y-24=0

We move all terms containing y to the left, all other terms to the right

3y=24

y=24/3

y=8

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