3(y-4)+y/2=9

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Solution for 3(y-4)+y/2=9 equation: 



3(y-4)+y/2=9

We move all terms to the left:

3(y-4)+y/2-(9)=0

We multiply parentheses

3y+y/2-12-9=0

We multiply all the terms by the denominator


3y*2+y-12*2-9*2=0

We add all the numbers together, and all the variables

y+3y*2-42=0

Wy multiply elements

y+6y-42=0

We add all the numbers together, and all the variables

7y-42=0

We move all terms containing y to the left, all other terms to the right

7y=42

y=42/7

y=6

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