3(y-4)-(4y-11)=y-2

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Solution for 3(y-4)-(4y-11)=y-2 equation: 



3(y-4)-(4y-11)=y-2

We move all terms to the left:

3(y-4)-(4y-11)-(y-2)=0

We multiply parentheses

3y-(4y-11)-(y-2)-12=0

We get rid of parentheses

3y-4y-y+11+2-12=0

We add all the numbers together, and all the variables

-2y+1=0

We move all terms containing y to the left, all other terms to the right

-2y=-1

y=-1/-2

y=1/2

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