3(y-4)-2=-3(-9y+2)-8y

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Solution for 3(y-4)-2=-3(-9y+2)-8y equation: 



3(y-4)-2=-3(-9y+2)-8y

We move all terms to the left:

3(y-4)-2-(-3(-9y+2)-8y)=0

We multiply parentheses

3y-(-3(-9y+2)-8y)-12-2=0



We calculate terms in parentheses: -(-3(-9y+2)-8y), so:

-3(-9y+2)-8y

We add all the numbers together, and all the variables

-8y-3(-9y+2)

We multiply parentheses

-8y+27y-6

We add all the numbers together, and all the variables

19y-6

Back to the equation:

-(19y-6)



We add all the numbers together, and all the variables

3y-(19y-6)-14=0

We get rid of parentheses

3y-19y+6-14=0

We add all the numbers together, and all the variables

-16y-8=0

We move all terms containing y to the left, all other terms to the right

-16y=8

y=8/-16

y=-1/2

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