3(y-4)-4(y-3)=y+3-(y-2)

Solution for 3(y-4)-4(y-3)=y+3-(y-2) equation:

Simplifying
3(y + -4) + -4(y + -3) = y + 3 + -1(y + -2)

Reorder the terms:
3(-4 + y) + -4(y + -3) = y + 3 + -1(y + -2)
(-4 * 3 + y * 3) + -4(y + -3) = y + 3 + -1(y + -2)
(-12 + 3y) + -4(y + -3) = y + 3 + -1(y + -2)

Reorder the terms:
-12 + 3y + -4(-3 + y) = y + 3 + -1(y + -2)
-12 + 3y + (-3 * -4 + y * -4) = y + 3 + -1(y + -2)
-12 + 3y + (12 + -4y) = y + 3 + -1(y + -2)

Reorder the terms:
-12 + 12 + 3y + -4y = y + 3 + -1(y + -2)

Combine like terms: -12 + 12 = 0
0 + 3y + -4y = y + 3 + -1(y + -2)
3y + -4y = y + 3 + -1(y + -2)

Combine like terms: 3y + -4y = -1y
-1y = y + 3 + -1(y + -2)

Reorder the terms:
-1y = y + 3 + -1(-2 + y)
-1y = y + 3 + (-2 * -1 + y * -1)
-1y = y + 3 + (2 + -1y)

Reorder the terms:
-1y = 3 + 2 + y + -1y

Combine like terms: 3 + 2 = 5
-1y = 5 + y + -1y

Combine like terms: y + -1y = 0
-1y = 5 + 0
-1y = 5

Solving
-1y = 5

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = -5

Simplifying
y = -5