3(y-4)-4=-5(-4y+4)-5y

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Solution for 3(y-4)-4=-5(-4y+4)-5y equation: 



3(y-4)-4=-5(-4y+4)-5y

We move all terms to the left:

3(y-4)-4-(-5(-4y+4)-5y)=0

We multiply parentheses

3y-(-5(-4y+4)-5y)-12-4=0



We calculate terms in parentheses: -(-5(-4y+4)-5y), so:

-5(-4y+4)-5y

We add all the numbers together, and all the variables

-5y-5(-4y+4)

We multiply parentheses

-5y+20y-20

We add all the numbers together, and all the variables

15y-20

Back to the equation:

-(15y-20)



We add all the numbers together, and all the variables

3y-(15y-20)-16=0

We get rid of parentheses

3y-15y+20-16=0

We add all the numbers together, and all the variables

-12y+4=0

We move all terms containing y to the left, all other terms to the right

-12y=-4

y=-4/-12

y=1/3

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