3(y-4)=(y+74)

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Solution for 3(y-4)=(y+74) equation: 



3(y-4)=(y+74)

We move all terms to the left:

3(y-4)-((y+74))=0

We multiply parentheses

3y-((y+74))-12=0



We calculate terms in parentheses: -((y+74)), so:

(y+74)

We get rid of parentheses

y+74

Back to the equation:

-(y+74)



We get rid of parentheses

3y-y-74-12=0

We add all the numbers together, and all the variables

2y-86=0

We move all terms containing y to the left, all other terms to the right

2y=86

y=86/2

y=43

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